parseFloat之后NaN,为何？

Question

23.18K 浏览2015/08/10驱动程序

0

Nim 0 2015/08/11 0条评论

db.col.find({state:”success”},{_id:0,amount:1}).forEach(function(x){printjson(x);});
{ “amount” : “10.00” }
{ “amount” : “10.00” }
{ “amount” : “6” }

db.col.find({state:”success”},{_id:0,amount:1}).forEach(function(x){printjson(parseFloat(x));});

NaN
NaN
NaN

score 0 · Answer 1 · 2015-08-11T04:17:13+00:00

db.col.aggregate({$match:{state:”success”}},{$group:{_id:”$pid”,total:{$sum: parseFloat(“$amount”)}}});

在SUM里面怎么再用parseFloat()
???

score 0 · Answer 2 · 2015-08-11T04:13:16+00:00

db.col.find({state:”success”},{_id:0,amount:1}).forEach(function(x){printjson(parseFloat(x.amount));});

10
10
6
6